answer:To find the arithmetic mean, we add the two numbers and divide by 2. The arithmetic mean of frac{7}{10} and frac{4}{5} is frac{frac{7}{10} + frac{4}{5}}{2} = frac{frac{35}{50} + frac{40}{50}}{2} = frac{frac{75}{50}}{2} = frac{frac{3}{2}}{2} = boxed{frac{3}{4}}. Therefore, frac{3}{4} is the arithmetic mean of frac{7}{10} and frac{4}{5}. The answer is: frac{3}{4}

answer:To solve for sqrt{1.0201}, we can relate it to the given sqrt{102.01}=10.1 by noticing a pattern in the decimal places. Starting with the given: sqrt{102.01} = 10.1 We want to find sqrt{1.0201}. Notice that 1.0201 is 102.01 divided by 100: 1.0201 = frac{102.01}{100} Therefore, we can write: sqrt{1.0201} = sqrt{frac{102.01}{100}} Since the square root of a quotient is the quotient of the square roots, and knowing sqrt{102.01} = 10.1, we have: sqrt{1.0201} = frac{sqrt{102.01}}{sqrt{100}} = frac{10.1}{10} Simplifying the fraction: sqrt{1.0201} = 1.01 Thus, the correct answer is: boxed{B}

answer:The `all()` function in Python takes an iterable (such as a list, tuple, or set) as an argument and returns `True` if all elements in the iterable are true. If at least one element is false, it returns `False`. In Python, the following values are considered false: - `False` - `0` (integer) - `0.0` (float) - `''` (empty string) - `[]` (empty list) - `{}` (empty dictionary) - `()` (empty tuple) - `None` All other values are considered true. Here are some examples to illustrate the usage of `all()`: ```python # All elements are true print(all([True, True, True])) # Output: True # At least one element is false print(all([True, False, True])) # Output: False # All elements are true (non-zero numbers) print(all([1, 2, 3])) # Output: True # At least one element is false (zero) print(all([1, 0, 3])) # Output: False # Empty iterable print(all([])) # Output: True ``` The last example might be counterintuitive, but `all([])` returns `True` because there are no elements in the iterable that are false. In addition to using `all()` with a list of boolean values, you can also use it with a generator expression to check if all elements in an iterable satisfy a certain condition: ```python # Check if all numbers in a list are greater than 0 numbers = [1, 2, 3, 4, 5] print(all(x > 0 for x in numbers)) # Output: True # Check if all strings in a list are non-empty strings = ['apple', 'banana', 'cherry'] print(all(s != '' for s in strings)) # Output: True ```

answer:Here's a simple Python program that uses a list comprehension to create a new list of only the even numbers from the original list: ```python # Original list of numbers numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] # List comprehension to create a new list of even numbers even_numbers = [x for x in numbers if x % 2 == 0] # Print the new list of even numbers print(even_numbers) ``` When you run this program, it will output: ``` [2, 4, 6, 8, 10] ``` This program works by iterating over each number `x` in the original list and checking if `x` is even by using the modulo operator (`%`). If `x` is even (i.e., `x % 2 == 0`), it is included in the new list of even numbers. Alternatively, you can also use the `filter()` function in combination with a lambda function to achieve the same result: ```python even_numbers = list(filter(lambda x: x % 2 == 0, numbers)) ``` However, list comprehensions are generally considered more Pythonic and readable than using `filter()` with a lambda function.