answer:To solve the problem, we need to find the equation that correctly represents the average annual growth rate of the regional GDP of Fujian Province over two years. The initial GDP in 2020 is 43903.89 billion yuan, and the GDP in 2022 is 53109.85 billion yuan. Let x be the average annual growth rate. The growth over two years can be modeled by applying the growth rate twice (compounded annually). Step 1: Write down the initial GDP and the GDP after two years. - Initial GDP in 2020: 43903.89 billion yuan - GDP in 2022: 53109.85 billion yuan Step 2: Model the growth over two years using the average annual growth rate x. - The formula to calculate the future value after two years of growth is given by the initial value multiplied by (1 + x) raised to the power of the number of years, which in this case is 2 because we are looking at the growth over two years. Step 3: Set up the equation based on the information given. - The equation that represents this situation is 43903.89(1+x)^2 = 53109.85. Step 4: Identify the correct equation from the given options. - Comparing the equation we derived with the options given, we find that option B: 43903.89(1+x)^2 = 53109.85 matches our equation. Therefore, the correct option that represents the average annual growth rate of the regional GDP of Fujian Province over these two years is: boxed{B}

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answer:Let's solve for the intersection of the two equations: 1. Original equation: [ y = a(x-h)^2 + d ] 2. Modified equation: [ y = a(x+3-h)^2 + d ] Setting these equal: [ a(x-h)^2 + d = a(x+3-h)^2 + d ] Thus, disregarding d from both sides: [ a(x-h)^2 = a(x+3-h)^2 ] Dividing through by a (assuming a neq 0): [ (x-h)^2 = (x+3-h)^2 ] This implies (x-h) = pm(x+3-h). Considering the positive case: [ x-h = x+3-h implies 0 = 3 ] This yields no solution. Considering the negative case: [ x-h = -(x+3-h) implies x-h = -x-3+h implies 2x = -3 ] [ x = -frac{3}{2} ] Substituting x = -frac{3}{2} into either equation: [ y = a(-frac{3}{2}-h)^2 + d ] Thus, the graphs intersect at left(-frac{3}{2}, aleft(-frac{3}{2}-hright)^2 + dright). Conclusion with boxed answer: The graphs intersect at left(-frac{3{2}, aleft(-frac{3}{2}-hright)^2 + dright)}. The final answer is B) At point boxed{(-frac{3}{2}, aleft(-frac{3}{2}-hright)^2 + d)}

answer:Hi Michael, I hope you're doing well. I just wanted to touch base about the student reports for our joint project. It seems they weren't submitted by the deadline, which is a bit concerning since it's a crucial part of the project. This delay has created some challenges on my end. I was under the impression that we were aligned on the timeline. Thanks for your help, and let's work together to get this sorted out. Best, Sarah